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vk · November 25th, 2012, 16:06

The important issue with men/women strength comparison is that women are generally smaller in size. A better comparison can be made by compensating the strength with the size.

Let’s assume that an average woman (A) carries an average man (B) and then this average man carries a large man (C). Common sense tells us that (B) will have harder time than (A). But let’s look at it more precisely.

At this point we consider that (A) (B) and (C) are similarly shaped, neither thin nor fat, just average. Said in other terms, (B) just looks as a reduction of (C). Also (A) looks as reduction of (B) except that she is a female.

Now let’s go further and assume that (B) is 1,15 times taller than (A) and that (C) is 1,15 times taller than (B). For instance (A) is 150 cm, (B) is 1,15 x 150 cm = 172 cm and (C) is 1,15 x 1,15 x 150 cm = 198 cm.

Now let’s compare the strength of (A) (B) (C), assuming that each of them has reasonable capacities compared to their sizes. Strength depends on the number of fibers in muscle sections so it can be calculated as a surface. For instance if (A) has 1000 fibers (B) will have 1,15 x 1,15 x 1000 = 1322 fibers and (C) will have 1,15 x 1,15 x 1,5 x 1,5 x 1000 = 1749 fibers (or maybe 1000 fibers but each of them 1,749 times larger in section).

How about weights now? Weight can be compared with a volume so here we go : (A) is 40 kg, (B) is 1,15 x 1,15 x 1,15 x 40 = 60,8 kg and (C) is 1,15 x 1,15 x 1,15 x 1,15 x 1,15 x 1,15 x 40 = 92,5 kg.

Now (A) has got 1000 fibers to hold 60,8 kg which means an effort of 60,8 grams per fiber. As for (B) he has got 1322 fibers to hold 92,5 kg which means 73,7 grams per fiber. So definitely the task is easier for (A).

That’s why your girl friends can carry you so easily: scalability, the old Galileo’s trick. Ants also know that. An ant can carry the weight of 50 ants. But an elephant will never carry the weight of 50 elephants.

November 25th, 2012, 16:06	#16
vk Administrator Join Date: Feb 2009 Posts: 626 : 3 For This Post 139 Total	The important issue with men/women strength comparison is that women are generally smaller in size. A better comparison can be made by compensating the strength with the size. Let’s assume that an average woman (A) carries an average man (B) and then this average man carries a large man (C). Common sense tells us that (B) will have harder time than (A). But let’s look at it more precisely. At this point we consider that (A) (B) and (C) are similarly shaped, neither thin nor fat, just average. Said in other terms, (B) just looks as a reduction of (C). Also (A) looks as reduction of (B) except that she is a female. Now let’s go further and assume that (B) is 1,15 times taller than (A) and that (C) is 1,15 times taller than (B). For instance (A) is 150 cm, (B) is 1,15 x 150 cm = 172 cm and (C) is 1,15 x 1,15 x 150 cm = 198 cm. Now let’s compare the strength of (A) (B) (C), assuming that each of them has reasonable capacities compared to their sizes. Strength depends on the number of fibers in muscle sections so it can be calculated as a surface. For instance if (A) has 1000 fibers (B) will have 1,15 x 1,15 x 1000 = 1322 fibers and (C) will have 1,15 x 1,15 x 1,5 x 1,5 x 1000 = 1749 fibers (or maybe 1000 fibers but each of them 1,749 times larger in section). How about weights now? Weight can be compared with a volume so here we go : (A) is 40 kg, (B) is 1,15 x 1,15 x 1,15 x 40 = 60,8 kg and (C) is 1,15 x 1,15 x 1,15 x 1,15 x 1,15 x 1,15 x 40 = 92,5 kg. Now (A) has got 1000 fibers to hold 60,8 kg which means an effort of 60,8 grams per fiber. As for (B) he has got 1322 fibers to hold 92,5 kg which means 73,7 grams per fiber. So definitely the task is easier for (A). That’s why your girl friends can carry you so easily: scalability, the old Galileo’s trick. Ants also know that. An ant can carry the weight of 50 ants. But an elephant will never carry the weight of 50 elephants.